Cooperative Zendo

Not the kind with cardstock and pawns. Mostly play by post Mafia so far.

Re: Cooperative Zendo

Postby Unbitwise » Thu Oct 13, 2016 10:13 am

Ah. I'm fine with that, but I had understood it otherwise.
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Re: Cooperative Zendo

Postby Lambda » Thu Oct 13, 2016 10:26 am

Neither begins with d or h, nor ends with j or p.
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Re: Cooperative Zendo

Postby DanielH » Thu Oct 13, 2016 10:30 am

That is a superset of my already-a-superset rule.

I did in fact guess aristodemocracy because if its length.

Let p be the smallest positive prime factor of the length of the word l; if pl the word fails*. Then a word is accepted iff only its first l/p letters have ascenders and only its last l/p have descenders. This does not mean ascenders or descenders must be present, only that if they are they are in the appropriate positions.

* The only time p > l is the empty string, because 2 is a factor of zero. Since the empty string is not well-formed, it should not matter if your rule gives a different answer in that case.
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Re: Cooperative Zendo

Postby Lambda » Thu Oct 13, 2016 10:34 am

Edit: withdrawn, ignore me
i has a reading comprehension wrote:xray
xylophone
xylophones
xerography
xylophonists
xenophobia
xenophobic
Last edited by Lambda on Thu Oct 13, 2016 10:46 am, edited 2 times in total.
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Re: Cooperative Zendo

Postby DanielH » Thu Oct 13, 2016 10:40 am

All of those except xray are forbidden by my known-superset rule. Did you miss it?
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Re: Cooperative Zendo

Postby Lambda » Thu Oct 13, 2016 10:44 am

Uh, yes. I withdraw those.

stucco
embryo
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Re: Cooperative Zendo

Postby Lambda » Thu Oct 13, 2016 11:30 am

interhyperlinguomonograms
unintercameroexcuseograms

(please excuse the highly dubious wordiness of these koans)
("monograms combining multiple hyperlanguages", "written documents bearing excuses, not addressed from one house of Congress to the other")
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Re: Cooperative Zendo

Postby Unbitwise » Thu Oct 13, 2016 11:49 am

DanielH wrote:Let p be the smallest positive prime factor of the length of the word l; if pl the word fails*. Then a word is accepted iff only its first l/p letters have ascenders and only its last l/p have descenders. This does not mean ascenders or descenders must be present, only that if they are they are in the appropriate positions.

*squints* I think you have it.

The actual rule is:

The string may be written in a rectangle of characters (left to right and top to bottom) such that only the top row has any ascenders and only the bottom row has any descenders.

I note that I failed to write down the requirement that it be a non-degenerate rectangle (having at least two rows and at least two columns) which I was judging koans by. Without that, it trivially accepts all words as 1-high rectangles.
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Re: Cooperative Zendo

Postby DanielH » Thu Oct 13, 2016 12:37 pm

Yeah, that seems equivalent; I specify the widest possible rectangle if you look at it that way, which always works if any rectangle does.
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Re: Cooperative Zendo

Postby Unbitwise » Thu Oct 13, 2016 12:57 pm

Well, you've won it.

The form of your guess suggests to me that my rule was too obscure (even if the way I designed it was less mathematical than the guess). Your opinion? (Lambda?)
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